[坑][自闭]1082 Read Number in Chinese （25 分)

2019-04-09

1082 Read Number in Chinese （25 分)

Given an integer with no more than 9 digits, you are supposed to read it in the traditional Chinese way. Output Fu first if it is negative. For example, -123456789 is read as Fu yi Yi er Qian san Bai si Shi wu Wan liu Qian qi Bai ba Shi jiu. Note: zero (ling) must be handled correctly according to the Chinese tradition. For example, 100800 is yi Shi Wan ling ba Bai.

Input Specification:

Each input file contains one test case, which gives an integer with no more than 9 digits.

Output Specification:

For each test case, print in a line the Chinese way of reading the number. The characters are separated by a space and there must be no extra space at the end of the line.

Sample Input 1:

1	-123456789

Sample Output 1:

1	Fu yi Yi er Qian san Bai si Shi wu Wan liu Qian qi Bai ba Shi jiu

Sample Input 2:

Sample Output 2:

1	yi Shi Wan ling ba Bai

作者: CHEN, Yue

单位: 浙江大学

时间限制: 400 ms

内存限制: 64 MB

代码长度限制: 16 KB

题意

给出一串数字，要求输出中文读法。

分析

看到这题我的内心是自闭的🙄。不过兵来将挡，水来土掩，刚（头铁）就完事了。

一开始考虑用string存数字，便于提取各位。后来发现还是用int更方便。

首先，把数字分成三部分。第9位（亿级），8-5位（万级），4-1位（个级）。这里就能体现出int的优越性了，如果使用string会非常麻烦。然后依次处理。万级的逻辑与个级类似，只不过多加了个Wan。

start用于控制开始输出，例如输入100。亿位万位都是0，显然不用输出0亿0万。当输出第一个不为0的数后，置start为1。

fisrt用于控制空格。第一个数之前不输出空格，其余数输出前需加空格

prtling用于控制是否需要输出0。

亿级（第9位）
逻辑比较简单。判断是否为0即可。如果不为0，输出。如果万位个位全为0，直接返回。
万级（8-5位）
首先判断是否为0。如果为0输出ling。否则计算千百十个位，依次处理。
1.千位。还是判断是否为0，如果为0且百十个不都为0（在千位这个判断好像可以省去），则输出ling。否则在千位不等于0时，输出x Qian。(x为千位数字)
2.百位。与千位类似。判断是否为0，如果为0且十个位不为0，则输出ling（这个判断不能省，1001百位的0需输出，1000则不用，）。否则百位不为0时，输出x Bai。
3.十位个位逻辑类似。
4.最后输出Wan。
个级（4-1位）
逻辑与万级类似

代码

代码虽然丑了点，但是逻辑还是比较易于理解的。事实上，处理个十百千位的逻辑类似，处理万级与个级的逻辑也类似，还是可以把代码写的好看的，只不过得多花费些功夫。

柳婼大佬的代码，写的很简洁，但我是不可能看懂的🤷🏻‍♂️

#include <iostream>
#include <vector>
#include <algorithm>
#include <deque>
#include <map>
#include <set>
#include <cstring>
#include <cmath>
#include <sstream>

using namespace std;
vector<string> num = {"ling", "yi", "er", "san", "si", "wu", "liu", "qi", "ba", "jiu"};

int main() {
    int n;
    cin >> n;
    if (n == 0) {
        cout << "ling";
        return 0;
    }
    if (n < 0) {
        cout << "Fu ";
        n = -n;
    }
    int part[3];
    part[0] = n / 100000000;
    part[1] = n % 100000000 / 10000;
    part[2] = n % 10000;
    int start = 0;//开始输出
    int first = 0;
    int prtling = 0;//打印了0
    for (int i = 0; i < 3; i++) {
        if (part[i] == 0 && start == 0)
            continue;
        if (i == 0) {
            first++ == 0 ? cout << "" : cout << " ";
            cout << num[part[0]] << " " << "Yi";
            start = 1;
            if (part[1] == 0 && part[2] == 0)
                return 0;
        } else if (i == 1) {
            if (part[i] == 0) {
                cout << " ling";
                prtling = 1;
            } else {
                int q = part[i] / 1000;
                part[i] = part[i] % 1000;
                int b = part[i] / 100;
                part[i] = part[i] % 100;
                int shi = part[i] / 10;
                int ge = part[i] % 10;

                if (q == 0 && prtling == 0 && start == 1 && (b != 0 || shi != 0 || ge != 0)) {
                    cout << " ling";
                    prtling = 1;
                } else if (q != 0) {
                    first++ == 0 ? cout << "" : cout << " ";
                    cout << num[q] << " Qian";
                    prtling = 0;
                    start = 1;
                }

                if (b == 0 && prtling == 0 && start == 1 && (shi != 0 || ge != 0)) {
                    cout << " ling";
                    prtling = 1;
                } else if (b != 0) {
                    first++ == 0 ? cout << "" : cout << " ";
                    cout << num[b] << " Bai";
                    prtling = 0;
                    start = 1;
                }

                if (shi == 0 && prtling == 0 && start == 1 && ge != 0) {
                    cout << " ling";
                    prtling = 1;
                } else if (shi != 0) {
                    first++ == 0 ? cout << "" : cout << " ";
                    cout << num[shi] << " Shi";
                    prtling = 0;
                    start = 1;
                }

                if (ge != 0) {
                    first++ == 0 ? cout << "" : cout << " ";
                    cout << num[ge];
                    prtling = 0;
                    start = 1;
                }
                cout << " Wan";
            }
        } else if (i == 2) {
            int q = part[i] / 1000;
            part[i] = part[i] % 1000;
            int b = part[i] / 100;
            part[i] = part[i] % 100;
            int shi = part[i] / 10;
            int ge = part[i] % 10;

            if (q == 0 && prtling == 0 && start == 1 && (b != 0 || shi != 0 || ge != 0)) {
                cout << " ling";
                prtling = 1;
            } else if (q != 0) {
                first++ == 0 ? cout << "" : cout << " ";
                cout << num[q] << " Qian";
                prtling = 0;
                start = 1;
            }

            if (b == 0 && prtling == 0 && start == 1 && (shi != 0 || ge != 0)) {
                cout << " ling";
                prtling = 1;
            } else if (b != 0) {
                first++ == 0 ? cout << "" : cout << " ";
                cout << num[b] << " Bai";
                prtling = 0;
                start = 1;
            }

            if (shi == 0 && prtling == 0 && start == 1 && ge != 0) {
                cout << " ling";
                prtling = 1;
            } else if (shi != 0) {
                first++ == 0 ? cout << "" : cout << " ";
                cout << num[shi] << " Shi";
                prtling = 0;
                start = 1;
            }

            if (ge != 0) {
                first++ == 0 ? cout << "" : cout << " ";
                cout << num[ge];
                prtling = 0;
                start = 1;
            }
        }

    }
    return 0;
}